(1/x^2-5x)=(x+7/x)-1

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Solution for (1/x^2-5x)=(x+7/x)-1 equation: 



(1/x^2-5x)=(x+7/x)-1

We move all terms to the left:

(1/x^2-5x)-((x+7/x)-1)=0



Domain of the equation: x^2-5x)!=0

x∈R





Domain of the equation: x)-1)!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

(1/x^2-5x)-((+x+7/x)-1)=0

We get rid of parentheses

1/x^2-5x-((+x+7/x)-1)=0

We calculate fractions

We do not support expression: x^3

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